Python Error - TypeError: input expected at most 1 arguments, got 3 -

can explain why can not use your_name in goal variable?

my_name = "bryson" my_age = 29 your_name = input ("what name? ") your_age = input ("what age? ") print ("my name is", my_name,", , am", my_age, "years old.") print ("your name is", your_name,", , are", your_age,".") print("thank buying book,", your_name,"!") goal = input ("what favorite part of book,", your_name, "?") print("awesome!") 

the error is:

goal = input ("what favorite part of book,", your_name, "?") typeerror: input expected @ 1 arguments, got 3 

you got error because in fact gave 3 arguments input function when expecting 1 (namely, string prompt).

in input ("what favorite part of book,", your_name, "?")            ---------------------------------------- , ---------, --- 

the underlined parts comma-separated arguments: string ("what ....book", variable your_name, , string, "?"

i think wanted was

goal = input("what favorite part of book, " + your_name + "?") 

here concatenation operator + combines ingredients single string -- , string 1 argument input expecting