javascript - How to access outer function variable in nested inner function in JS -

i new js , having doubt below example. please see inline comments.

function outer() {  	var x = 5;  	console.log("outer",x); // prints 5  	console.log("-----------");  	function inner() {  		var x = 6;  		console.log("inner",x); // prints 6  		console.log("outer",x); // prints 6. how print 5  		console.log("-----------");  		function _inner() {  			var x = 7;  			console.log("_inner",x); // prints 7  			console.log("inner",x); // prints 7. how print 6  			console.log("outer",x); // prints 7. how print 5  			console.log("-----------");  		}  		_inner();  	}  	inner();  }  outer();

may helps you. assign variables nested functions because therefore clear varible should used have differ each other in way(name or via namespace):

function outer() {     var x = 5;     // or via namespace     // var out = { x : 5 };     console.log("outer",x); // 5     console.log("-----------");     function inner() {         inner.x = 6;         console.log("inner",inner.x); // 6         console.log("outer",x); // 5         console.log("-----------");         function _inner() {             _inner.x = 7;             console.log("_inner",_inner.x); // 7             console.log("inner",inner.x); // 6             console.log("outer",x); // 5             // namespace              // console.log("outer",out.x); // 5             console.log("-----------");         }         _inner();     }     inner(); } outer(); 

in example 2 of 3 varibles assign(not outer x) functions because otherwise assess outer.x outside outer function , assign value:

function outer(){    outer.x = 5;    ... } // assign value outside outer function outer.x = 34; 

but when local variable defined:

function outer(){    var x = 23; } 

then there no chance assign local variable(x) value outside outer function.