Find out if file pointer is at EOF in Python -

i trying find out whether file pointer @ eof in example code: (edited)

f = open("test.dat")  somefunctiondoingstuffon_f(f)  if f == eof:         # keep important in case     print "eof reached" else:     print "not eof" 

but not know if there available in python.

i have edited question adding somefunctiondoingstuffon_f(f), because might not know happened f before hand. excludes approaches.

based on martijns comment can use tell don't see how going make difference:

import os  r.f.seek(0, os.seek_end) n = r.f.tell() r.f.seek(0)  while r.f.tell() < n:     line = r.f.readline()     print(line)     print("not @ eof") print("at eof") 

where r.f file object class in previous question cannot use tell in same way using islice.

or using using if's more logic in question:

import os  r.f.seek(0, os.seek_end) n = r.f.tell() r.f.seek(0)  while true:     if r.f.tell() != n:         line = r.f.readline()         print(line)         print("not @ eof")     else:          print("at eof")          break