lua - How do I make my add command find the value of the first variable and the second then add them together? -

vars = {} values = {}  function open(file)     lex(file) end  function lex(file)     local data = io.open(file, "r")     char in data:lines()         --print         if char:sub(1, 6) == "print:"             print(char:sub(7))         end         --integer         if char:sub(1, 2) == "v:"             vars [#vars + 1] = char:sub(3, 5)             if char:sub(6, 6) == "="                 values [#values + 1] = char:sub(7)             end             --print("name:"..vars [#vars]..", ".."value:"..values [#values])         end         --add         if char:sub(1, 4) == "add:"             if char:sub(5, 7) == vars[#vars]                 if char:sub(8, 8) == ","                     if char:sub(9, 11) == vars[#vars]                         print(values[#values] + values[#values])                         --print(vars[#vars])                     end                 end             end         end     end     --debug purposes     --[[     k, v in pairs(vars)         print(k, v)     end     b, in pairs(values)         print(b, a)     end     --]] end  function run()     while true         print("open file")         file = io.read()         print("file name:"..file)         print("")         lex(file)         print("")     end end  run() 

basically says "--add" want variable set name wrote down in text file the other set same name example: v:var=12 (nextline) v:vr2=10 (nextline) add:var,vr2, add values set it

you're on right track. changes make put comes after v: key in vars table, , set comes after = value, so:

if char:sub(1,2) == "v:" , char:sub(6, 6) == "="   vars[char:sub(3,5)] = tonumber(char:sub(7)) end 

then, have add function this:

function add_vars(one, two)   return vars[one] + vars[two] end 

at least, think understand you're wanting. if it's not, you'll want go more detail getting , you're expecting.