python - regex, how to exlude search in match -

might bit messy title, question simple.
got in python:

string = "start;some;text;goes;here;end" 

the start; , end; word @ same position in string.
want second word some in case. did:

import re string = "start;some;text;goes;here;end" word = re.findall("start;.+?;" string) 

in example, there might few things modify make more appropriate, in actual code, best way.

however, string start;some;, search characters included in output. index both ;, , extract middle part, there have way actual word, , not junk too?

no need regex in opinion, need capture group here.

word = re.findall("start;(.+?);", string) 

another improvement i'd suggest not using .. rather more specific, , looking else ;, delimiter.

so i'd this:

word = re.findall("start;([^;]+);", string)