c++ - Qt 5, get the mouse position in a screen -

first of all, i'd mention found related post how mouse position on screen in qt? "just didn't work" me. made tests, , results didn't work expected, decided make new post talk test made , find alternative solution.

that's code used make test:

qscreen *screen0 = qapplication::screens().at(0); qscreen *screen1 = qapplication::screens().at(1);  printf("screen0 %s \n", screen0->name().tostdstring().c_str()); printf("screen1 %s \n", screen1->name().tostdstring().c_str());  // position on first screen. qpoint pos0 = qcursor::pos(screen0);  // position on second screen. qpoint pos1 = qcursor::pos(screen1);  printf("pos 0: %d, %d \n", pos0.x(), pos0.y()); printf("pos 1: %d, %d \n", pos1.x(), pos1.y());  // position without screen. qpoint pos = qcursor::pos(); printf("pos: %d, %d \n", pos.x(), pos.y()); 

what expecting, 1 screen return valid position, since cursor @ 1 screen, not on both. it's not case, both positions (pos0 , pos1) has same value, can see on output:

screen0 dvi-d-0  screen1 hdmi-0  pos 0: 1904, 1178  pos 1: 1904, 1178  pos: 1904, 1178  

since both positions has same values, can't know @ screen cursor. don't know if that's normal behavior or bug, since documentation doesn't happens when screen argument isn't screen mouse is.

my idea, open/launch application (executed qt daemon must detect selected screen) screen mouse is. know libx11 it's possible, because did in past, need work qt 5, , can't figure out how detect selected screen qt.

i made other tests, using qapplication , qdesktopwidget classes no luck.

that's weird. workaround, try this:

qpoint globalcursorpos = qcursor::pos(); int mousescreen = qapp->desktop()->screennumber(globalcursorpos); 

now know screen cursor in. find cursor position within screen doing this:

qrect mousescreengeometry = qapp->desktop()->screen(mousescreen)->geometry(); qpoint localcursorpos = globalcursorpos - mousescreengeometry.topleft();