php - How to pass more than one argv variable using add slashes? -
i wondered right syntax passing more 1 variable using add slashes? tried many variation until now:
exec('php email.php "'.addslashes($body).'"' . "'.addslashes($msg).'"'); exec('php email.php "'.addslashes($body).'"' + "'.addslashes($msg).'"'); exec('php email.php "'.addslashes($body).'"' & "'.addslashes($msg).'"'); exec('php email.php "'.addslashes($body, $msg).'"'');
i have check example passing 1 argv , it's working fine:
exec('php email.php "'.addslashes($body).'"');
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the php email.php waiting in $argv 2 inputs in order run right. therefore main issue how pass him in 1 time 2 parameters: $body & $msg let if ran web page this:
www.mydomain/email.php?body=value1&msg=value2
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